If the lines 3y = 4x – 1 and qy = x + 3 are parallel to each other, the value of q is
- A.
–^{4}/_{3} - B.
–^{3}/_{4} - C.^{4}/_{3}
- D.^{3}/_{4}
Correct Answer: Option D
Explanation
If the line 3y = 4x – 1 is parallel t[ line qy = x + 3
Implies gradient of 3y = 4x – 1
Y = ^{4}/_{3}x – ^{1}/_{3}
∴Gradient = ^{4}/_{3}
Gradient of line qy = x + 3
Y = ^{1}/_{q}x + ^{3}/_{q}
∴ Gradient = ^{1}/_{q}^{4}/_{3} = ^{1}/_{q}
4q = 3
Q = ^{3}/_{4}